U.S. Beacon April 16, 2012

Keosauqua, IA

Van Buren County, Iowa

Latitude: 40.732089     Longitude: -91.963027
Population 1,076 (2005)
Elevation of Keosauqua, Iowa: 700 feet
KEOSAUQUA is located in VAN BUREN county, Iowa at latitude 40.732089 and longitude -91.963027 with an elevation of 700 feet. The population of KEOSAUQUA is 1,076 as of the year 2005 with a population growth of 0.94% from the year 2000 through 2005. The most common zip code of KEOSAUQUA is 52565.

More data for Keosauqua,IA: Demographic Profile - Social Profile - Economic Profile - Housing Profile

Population 2005: 1,076
Population 2004: 1,073
Population 2003: 1,069
Population 2002: 1,070
Population 2001: 1,059
Population 2000: 1,066 (2000 Census)
Population 1990: 1,020 (1990 Census)

Population Growth 2000 to 2005: 0.94%
Population Growth 1990 to 2000: 4.51%

Population (2000 Census): 1,066
Male: 465 (43.62%)
Female: 601 (56.38%)

Median age: 48.60 years

Races, 2000 Census:
White: 98.50%
Two or more races: 0.94%
Asian: 0.28%
Black or African American: 0.19%
Hispanic or Latino: 0.09%

Housing Units: 505 (2000 Census)
Land Area: 1.4628 square miles
Water Area: 0.1180 square miles

Most populous zip code: 52565

Cities & Towns nearby Keosauqua

Mount Sterling, IA 8mi S
Cantril, IA 8.2mi SW
Bonaparte, IA 8.8mi ESE
Leando, IA 9.5mi NW
Douds, IA 9.8mi NW
Birmingham, IA 10.2mi N
Stockport, IA 11mi NE
Milton, IA 11.2mi WSW
Selma, IA 13.2mi NW
Farmington, IA 13.3mi ESE
More data for Keosauqua,IA: Demographic Profile - Social Profile - Economic Profile - Housing Profile

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