U.S. Beacon January 6, 2014

Tennant, IA

Shelby County, Iowa

Latitude: 41.594246     Longitude: -95.441976
Population 69 (2005)
Elevation of Tennant, Iowa: 1382 feet
TENNANT is located in SHELBY county, Iowa at latitude 41.594246 and longitude -95.441976 with an elevation of 1382 feet. The population of TENNANT is 69 as of the year 2005 with a population growth of -5.48% from the year 2000 through 2005. The most common zip code of TENNANT is 51574.

More data for Tennant,IA: Demographic Profile - Social Profile - Economic Profile - Housing Profile

Population 2005: 69
Population 2004: 70
Population 2003: 71
Population 2002: 72
Population 2001: 73
Population 2000: 73 (2000 Census)
Population 1990: 78 (1990 Census)

Population Growth 2000 to 2005: -5.48%
Population Growth 1990 to 2000: -6.41%

Population (2000 Census): 73
Male: 34 (46.58%)
Female: 39 (53.42%)

Median age: 47.80 years

Races, 2000 Census:
White: 100.00%

Housing Units: 32 (2000 Census)
Land Area: 0.7135 square miles

Most populous zip code: 51574

Cities & Towns nearby Tennant

Shelby, IA 5.5mi S
Portsmouth, IA 5.6mi NW
Persia, IA 6.7mi W
Harlan, IA 7.5mi NE
Westphalia, IA 9mi NNE
Panama, IA 9.3mi N
Avoca, IA 9.6mi SE
Minden, IA 10.2mi SSW
Earling, IA 12.6mi N
Kirkman, IA 13mi NE
More data for Tennant,IA: Demographic Profile - Social Profile - Economic Profile - Housing Profile

US Beacon Home